lg^2 x^2+3 lg1/x = 1

Conditii de existenta: 1/x>0,x≠0
(2lgx)^2+3(lg1-lgx)=1⇔4lg²x-3lgx-1=0
Notam: lgx=y,y∈R
4y²-4y-1=0, cu solutiile y=1 si y=-1/4
y=1⇔lgx=lg10⇔x=1
y=-1/4⇔lx=lg10^-1/4⇔x=10^(-1/4)