can someone please explain to me how to do this.

y = x² - 4x + 4
y = 2x - 4

Find intersection of L and C:
x² - 4x + 4 = 2x - 4
x² - 6x + 8 = 0
(x - 2)(x - 4) = 0
x = 2 or x = 4

When x = 2 , y = 2(2) - 4 = 0
When x = 4, y = 2(4) - 4 = 4

Points of intersection = A(2, 0) and B(4, 4)

Find the length of AB:

[tex] \text {Length of AB}= \sqrt{(4-0)^2 + (4-2)^2} = \sqrt{16 + 4} = \sqrt{20} = 4.47 \text{ units}[/tex]

Answer: 4.47 units