Find the product. (a2)(2a3)(a2 – 8a + 9) 2a7 – 16a6 + 18a5 2a7 – 16a6 – 18a5 2a8 – 16a7 + 18a6 2a12 – 16a7 + 18a6 consider the degree of each polynomial in the
Question
2 Answer

1. User Answers PiaDeveau
Answer: [tex]2x^7 16a^6 +18a^5[/tex]
Stepbystep explanation: Given expression [tex](a^2)(2a^3)(a^28a + 9)[/tex].
The first factor [tex](a^2)[/tex] has a degree of : 2 because power of a is 2.
The second factor [tex](2a^3)[/tex] has a degree of : 3 because power of a is 3.
The third factor [tex](a^28a + 9)[/tex] has a degree of : 2 because highest power of a is 2.
Let us multiply them now:
[tex](a^2)(2a^3)(a^28a + 9).[/tex]
First we would multiply [tex](a^2)(2a^3)[/tex].
According to product rule of exponents, we would add the powers of a.
Therefore,
[tex](a^2)(2a^3) = 2a^{2+3}= 2a^5[/tex]
Now, we need to distribute [tex]2a^5[/tex] over [tex](a^28a + 9)[/tex]
Therefore,
[tex](2a^5)(a^28a + 9)= 2a^{5+2} 16a^{5+1}+18a^5[/tex]
=[tex]2x^7 16a^6 +18a^5[/tex]
Highest power of resulting polynomial [tex]2x^7 16a^6 +18a^5[/tex] is 7.
Therefore, The product has a degree of 7.

2. User Answers denve0range21
Answer:
Stepbystep explanation:
A
2a7 – 16a6 + 18a5