# Calculate the number of moles of naoh present in 11.2 ml of 2.50 m naoh solution

Chemistry

## Question

Calculate the number of moles of naoh present in 11.2 ml of 2.50 m naoh solution

• ### 1. User Answers Anonym

Let's review what is given in this problem.

The volume of the solution is 11.2 milliliters, which is 0.0112 liters (multiply 11.2 mL with 1 L / 1000 mL to get 0.0112).

The molar concentration is 2.5 M. This means that there are 2.5 moles of NaOH per liter in the solution.

Multiply the volume and the molar concentration to get the moles of NaOH in the solution.

$$\text{moles of NaOH} = 0.0112 \: \text{Liter} \times \dfrac{2.5 \: \text{moles}}{1 \: \text{Liter}}$$

The "Liter" will cancel out, leaving only moles.
After using a calculator (or computing by hand), you should get the following value:

$$0.028 \: \text{moles}$$

Since the given values were given with 3 significant figures, let's change this answer so there are 3 significant figures.

Thus, your final answer is $$0.0280 \: \text{moles}$$